Answer :
Final answer:
To raise the core body temperature of a person who weighs 186 lbs (84.5 kg) by 1°C, it would require approximately 212 kJ of heat, by utilizing the formula q = mcΔT, where m = mass, c = specific heat and ΔT = change in temperature.
Explanation:
The question relates to the concept of specific heat, a topic in physics. The specific heat of water is 1 cal/gram °C, which equals 4.184 joules (J)/gram °C. Using this information, we can calculate how much energy it would take to raise the core body temperature of a person who weighs 186 lbs (which equals about 84.5 kg) by one degree Celsius. We know that the human body is approximately 60% water, so we would need to calculate the specific heat for 50.7 kg of water (which is 60% of 84.5 kg).
Since the formula to calculate the heat (q) is q = mcΔT, where m is mass, c is the specific heat, and ΔT is the change in temperature, we substitute in our values to find: q = (50.7 kg)(4.184 kj/kg °C)(1°C). Therefore, it requires approximately 212 kJ of heat to raise the core body temperature of a person who weighs 186 lbs by 1°C.
Learn more about Specific Heat here:
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