High School

A person riding a Ferris wheel with a diameter of 50 feet travels once around the wheel in 5 minutes. What is the average speed of the rider in feet per second (rounded to the nearest hundredth of a foot per second)?

A. 0.87 ft/s
B. 1.57 ft/s
C. 3.14 ft/s
D. 6.28 ft/s

Answer :

Final answer:

The average speed of a rider on a Ferris wheel with a diameter of 50 feet that completes one rotation in 5 minutes is 0.5233 feet per second, which does not match any of the options provided. None of the options are correct.

Explanation:

A Ferris wheel with a diameter of 50 feet will have a circumference, which is the distance traveled in one rotation, given by the formula C = π × d, where C is the circumference and d is the diameter of the wheel.

Therefore, C = 3.14 × 50 feet = 157 feet (rounded to the nearest foot). If the Ferris wheel takes 5 minutes to complete one rotation, we need to convert this time into seconds to find the average speed in feet per second (ft/s).

5 minutes is equal to 300 seconds. Finally, we calculate the average speed, v, by dividing the total distance traveled, C, by the time, t: v = C/t = 157 feet / 300 seconds = 0.5233 ft/s.

To answer the student's question, none of the options provided (a, b, c, d) exactly match the calculated average speed, so it appears there may have been a mistake in the options provided.

None of the options are correct.