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A performer seated on a trapeze is swinging back and forth with a period of 8.87 seconds. If she stands up, raising the center of mass of the trapeze-performer system by 31.5 cm, what will be the new period of the system?

Answer :

Final answer:

The new period of the system can be calculated using the equation T2 = T1 * sqrt(L1/L2), where T1 is the original period, L1 is the original length, T2 is the new period, and L2 is the new length.

Explanation:

The period of a swinging pendulum is affected by the length of the pendulum. When the performer stands up on the trapeze, the length of the system increases. The period of the system can be calculated using the equation:

T2 = T1 * sqrt(L1/L2)

where T1 is the original period, L1 is the original length, T2 is the new period, and L2 is the new length. Plugging in the given values, we find that the new period of the system is:

T2 = 8.87 * sqrt((L1 + 0.315)/L1)

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