A patient’s temperature for five days after surgery taken at 7 AM each morning was recorded as 100.8, 101.2, 100.9, 100.2, and 99.8. Which of the following was the patient’s average temperature after surgery?
Answer :
Given:
[tex]100.8,101.2,100.9,100.2\text{ and 99.8}[/tex][tex]\begin{gathered} \text{Average}=\frac{100.8+101.2+100.9+100.2+99.8}{2} \\ =\frac{502.9}{5} \\ =100.58 \end{gathered}[/tex]