High School

A pair of parallel lines is cut by a transversal. What are the measures of the two marked angles?

Given:
\[ 3x + 10x + 17 \]

A. 11.29 degrees and 31.3 degrees
B. 137 degrees and 137 degrees
C. 137 degrees and 43 degrees
D. 43 degrees and 43 degrees

Answer :

Final answer:

To find the measures of the marked angles formed by a pair of parallel lines and a transversal, solve the given equations. Combine like terms and set the equation equal to find the value of x, and substitute it back to find the measures of the angles.

Explanation:

A pair of parallel lines cut by a transversal creates several angles. In this case, the two marked angles are 3x + 10x + 17 and a - 11.29 degrees. To find the measures of these angles, we need to solve the equations.

First, combine like terms for the angle 3x + 10x + 17. This simplifies to 13x + 17.

Next, set the equation for angle 3x + 10x + 17 equal to a - 11.29. Solve for x and substitute its value back into the equation for the angle to find its measure.