High School

A nearsighted man can clearly see objects up to a distance of 1.5m. Calculate the power of the lens of the spectacles necessary for the remedy of this defect. A. −0.37D B. −67D C. −0.67D D. −37D

Answer :

Final answer:

To remedy the nearsightedness, a lens power of approximately -0.035 D is necessary.

Explanation:

To calculate the power of the lens of the spectacles necessary to remedy a nearsightedness, we need to determine the lens power that will produce an image 30.0 cm from the eye for an object at infinity. We can use the formula P = 1/f, where P is the optical power of the lens and f is the focal length. In this case, we want the image distance di to be -28.5 cm when the object distance do is ∞.

Substituting the given values, we can solve for the lens power:

P = 1/f = 1/(-28.5 cm) = -0.035 D

Therefore, the power of the lens of the spectacles necessary for the remedy of this nearsightedness is approximately -0.035 D.

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