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A mixture of air and water vapor weighs 84 kg. If the water vapor weighs 3.1 kg, determine the humidity of the air.

Answer :

Question: A mixture of air and water vapor weighs 84 kg. If the water vapor weighs 3.1 kg, determine the humidity of air.

The humidity of the air in the mixture is approximately 3.83%.



To determine the humidity of air, we need to find the mass of the air in the mixture. We can do this by subtracting the mass of the water vapor from the total mass of the mixture.

Given:
Total mass of the mixture = 84 kg
Mass of the water vapor = 3.1 kg

Step 1: Subtract the mass of the water vapor from the total mass of the mixture.
Mass of the air = Total mass of the mixture - Mass of the water vapor
Mass of the air = 84 kg - 3.1 kg
Mass of the air = 80.9 kg

Step 2: Calculate the humidity of air.
Humidity of air = (Mass of the water vapor / Mass of the air) * 100
Humidity of air = (3.1 kg / 80.9 kg) * 100
Humidity of air ≈ 3.83%

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