A marshmallow is dropped from a 5.71-meter high pedestrian bridge, and 0.921 seconds later, it lands right on the head of an unsuspecting person walking underneath. How tall is the person with the marshmallow on her head?

a. 1.75 m
b. 1.70 m
c. 1.66 m
d. 1.51 m
e. 1.55 m
f. 1.89 m
g. 1.49 m
h. 1.62 m

The person's approximate height would be 1.29 meters, which falls closest to option c: 1.66 meters. This is calculated by understanding the physics of free fall and using the known variables of time and initial height.

Explanation:

The subject asked pertains to Physics, particularly kinematics, the study of motion. In free fall situations, such as dropping a marshmallow from a bridge, we use the formula d = 0.5gt² to find the distance fallen, where d is the distance fallen, g is the acceleration due to gravity (approximately 9.8m/s² on Earth), and t is the time it took to fall. In this case, the marshmallow has fallen for 0.921 seconds from a 5.71 meter high bridge.

If we plug into our formula, we find that the marshmallow fell approximately 4.42 meters (0.5 * 9.8 * 0.921²). So, we find the height of the person by subtracting this distance from the height of the bridge (5.71 - 4.42). This gives us approximately 1.29 meters. None of the options provided are exactly correct, but the closest one to 1.29 meters is option c: 1.66 meters

Learn more about Free Fall & Kinematics here:

https://brainly.com/question/29207036

#SPJ3