Answer :
When a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, then the acceleration of the box would be 3.6363 meters/second².
What is Newton's second law?
Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum. The mathematical expression for Newton's second law is as follows
F = ma
As given in the problem if a man pushes a 35.2 kg box across a frictionless floor with a force of 128 N, we have to calculate the acceleration of the box
Force = mass ×acceleration
128 = 35.2 × acceleration
acceleration = 128/35.2
= 3.6363 meters/second².
Thus, the acceleration of the box would be 3.6363 meters/second².
Learn more about Newton's second law from here,
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The formula for Force is F = MA
F = 128N.
M = 35.2kg.128
= 35.2A
Divide both sides by 35.2
A = ~3.636
So the answer is 3.636 m/s².
F = 128N.
M = 35.2kg.128
= 35.2A
Divide both sides by 35.2
A = ~3.636
So the answer is 3.636 m/s².
