A landscaper mows lawns for at least 3 hours but not more than 6 hours. The landscaper can mow [tex]44,000 \, \text{ft}^2[/tex] per hour. The function [tex]f(t) = 44,000 t[/tex] represents the number of square feet the landscaper can mow in [tex]t[/tex] hours.

What is the practical range of the function?

A. All real numbers from 132,000 to 264,000, inclusive
B. All real numbers
C. All multiples of 44,000 between 132,000 and 264,000, inclusive
D. All real numbers from 3 to 6, inclusive

To find the practical range of the function [tex]$ f(t) = 44,000t $[/tex], which represents the number of square feet a landscaper can mow in [tex]$ t $[/tex] hours, let's go through the steps:

1. Identify the range for [tex]$ t $[/tex]: The landscaper mows lawns for at least 3 hours and no more than 6 hours. Therefore, the possible values for [tex]$ t $[/tex] are 3, 4, 5, and 6.

2. Calculate the corresponding output values of the function [tex]$ f(t) $[/tex]:

- For [tex]$ t = 3 $[/tex], the area mowed is:
[tex]\[
f(3) = 44,000 \times 3 = 132,000
\][/tex]

- For [tex]$ t = 4 $[/tex], the area mowed is:
[tex]\[
f(4) = 44,000 \times 4 = 176,000
\][/tex]

- For [tex]$ t = 5 $[/tex], the area mowed is:
[tex]\[
f(5) = 44,000 \times 5 = 220,000
\][/tex]

- For [tex]$ t = 6 $[/tex], the area mowed is:
[tex]\[
f(6) = 44,000 \times 6 = 264,000
\][/tex]

3. Determine the practical range of the function: The practical range includes all possible outputs from the function based on the given constraints for [tex]$ t $[/tex]. Therefore, the range covers:
[tex]\[
132,000, 176,000, 220,000, \text{ and } 264,000
\][/tex]

By listing these possible areas that can be mowed, we find that the practical range of the function is:
- All multiples of 44,000 between 132,000 and 264,000, inclusive.

This means the correct answer is:
"all multiples of 44,000 between 132,000 and 264,000, inclusive."