High School

A horizontal force of 300.0 N is used to push a 145-kg mass 30.0 m horizontally in 3.00 s.

(A) Calculate the work done on the mass.

(B) Calculate the power developed.

Answer :

Final answer:

The work done on the mass is 9,000 J and the power developed in the process is 3,000 W.

Explanation:

In physics, work done is defined as the force multiplied by the displacement of an object when that force is applied. This can be calculated using the equation Work = Force x Distance.

(A) Here, a 300.0 N horizontal force is used to push a mass a distance of 30.0 m. The work done can therefore be calculated by multiplying the force (300.0 N) by the distance (30.0 m), equating to 9,000 J (Joules).

(B) Power, on the other hand, is the work done per unit time. It can be calculated using the equation Power = Work / Time. In this case, the time taken to move the mass is 3.00 s, so the power developed can be calculated by dividing the work done (9,000 J) by the time (3.00 s), resulting in 3,000 W (Watts).

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Final answer:

The work done on the 145-kg mass is 9000.0 Joules and the power developed is 3000.0 Watts.

Explanation:

(A) The work done on an object by a force is the force multiplied by the distance over which the force is applied. In this case, it is 300.0 N times 30.0 m, which equals 9000.0 Joules.

(B) Power is the work done per unit time, so it's the work done (which we just found to be 9000 Joules) divided by the time it takes (3.00 s), which equals 3000.0 Watts.

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