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------------------------------------------------ A grindstone increases in angular speed from 4.00 rad/s to 12.00 rad/s in 4.00 s. Through what angle does it turn during that time interval if the angular acceleration is constant?

A. 8.00 rad
B. 12.0 rad
C. 16.0 rad
D. 32.0 rad
E. 64.0 rad

Angular acceleration is the term used to describe the temporal pace at which angular velocity varies. Radians per second is the accepted unit of measurement. Consequently, = d d t. Angular acceleration is also known as rotational acceleration.

Angular acceleration can be calculated by dividing the angular velocity by the acceleration duration. (t). Use pi instead, or the drive speed (n) divided by the acceleration time (t) multiplied by 30. The usual SI unit for the rotational acceleration that results from this equation is radians per second squared (Rad/sec2).

Through what angle does it turn during that time interval if the angular acceleration is constant:

v(initial) = 4rad/s

v(final) = 12

t = 4 sec

a = ?

v(final) = v(initial) + at

12 = 4 + a(4)

a = 2 rad/sec2

s = ?

v(initial) = 4rad/s

v(final) = 12

a = 2rad/sec2

[tex]v(final)^2 = v(initial)^2 + 2as[/tex]

[tex]12^2 = 4^2 + 2(2)(s)[/tex]

144 = 16 + 4s

s = 32 rads

d) 32.0rad.

To learn more about angular acceleration, refer to:

brainly.com/question/20912191

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