Answer :
We are given that the silo consists of a cylindrical part and a hemispherical cap. The diameter of the silo is $4.4$ meters, so the radius is
$$
r = \frac{4.4}{2} = 2.2 \text{ m}.
$$
The cylindrical part has a height of $6.2$ meters.
---
**Step 1. Calculate the volume of the cylinder**
The volume of a cylinder is given by
$$
V_{\text{cylinder}} = \pi r^2 h,
$$
where $r = 2.2$ m and $h = 6.2$ m. Substituting the values (using $\pi = 3.14$):
$$
V_{\text{cylinder}} = 3.14 \times (2.2)^2 \times 6.2.
$$
First, calculate the square of the radius:
$$
(2.2)^2 = 4.84.
$$
Then multiply by the height and $\pi$:
$$
V_{\text{cylinder}} \approx 3.14 \times 4.84 \times 6.2 \approx 94.22512 \text{ m}^3.
$$
---
**Step 2. Calculate the volume of the hemisphere**
The volume of a hemisphere is given by
$$
V_{\text{hemisphere}} = \frac{2}{3} \pi r^3.
$$
First, compute the cube of the radius:
$$
(2.2)^3 = 2.2 \times 2.2 \times 2.2 \approx 10.648.
$$
Now, substitute the values:
$$
V_{\text{hemisphere}} \approx \frac{2}{3} \times 3.14 \times 10.648 \approx 22.28981 \text{ m}^3.
$$
---
**Step 3. Calculate the total volume**
The total volume of the silo is the sum of the volume of the cylinder and the volume of the hemisphere:
$$
V_{\text{total}} = V_{\text{cylinder}} + V_{\text{hemisphere}} \approx 94.22512 + 22.28981 \approx 116.51493 \text{ m}^3.
$$
Finally, rounding to the nearest tenth gives
$$
V_{\text{total}} \approx 116.5 \text{ m}^3.
$$
---
Thus, the approximate total volume of the silo is $\boxed{116.5 \text{ m}^3}$.
$$
r = \frac{4.4}{2} = 2.2 \text{ m}.
$$
The cylindrical part has a height of $6.2$ meters.
---
**Step 1. Calculate the volume of the cylinder**
The volume of a cylinder is given by
$$
V_{\text{cylinder}} = \pi r^2 h,
$$
where $r = 2.2$ m and $h = 6.2$ m. Substituting the values (using $\pi = 3.14$):
$$
V_{\text{cylinder}} = 3.14 \times (2.2)^2 \times 6.2.
$$
First, calculate the square of the radius:
$$
(2.2)^2 = 4.84.
$$
Then multiply by the height and $\pi$:
$$
V_{\text{cylinder}} \approx 3.14 \times 4.84 \times 6.2 \approx 94.22512 \text{ m}^3.
$$
---
**Step 2. Calculate the volume of the hemisphere**
The volume of a hemisphere is given by
$$
V_{\text{hemisphere}} = \frac{2}{3} \pi r^3.
$$
First, compute the cube of the radius:
$$
(2.2)^3 = 2.2 \times 2.2 \times 2.2 \approx 10.648.
$$
Now, substitute the values:
$$
V_{\text{hemisphere}} \approx \frac{2}{3} \times 3.14 \times 10.648 \approx 22.28981 \text{ m}^3.
$$
---
**Step 3. Calculate the total volume**
The total volume of the silo is the sum of the volume of the cylinder and the volume of the hemisphere:
$$
V_{\text{total}} = V_{\text{cylinder}} + V_{\text{hemisphere}} \approx 94.22512 + 22.28981 \approx 116.51493 \text{ m}^3.
$$
Finally, rounding to the nearest tenth gives
$$
V_{\text{total}} \approx 116.5 \text{ m}^3.
$$
---
Thus, the approximate total volume of the silo is $\boxed{116.5 \text{ m}^3}$.
