College

A force of 300 N is used to push a 145 kg mass 30 m horizontally in 3 seconds.

1. What is the work done on the mass?
2. What is the power?

Answer :

Answer:

The power exerted is 3000 Watts, the work done by the force is 9000 Joules, and the power is 3000 Watts.

Explanation:

The work done (W) is given by the formula:

W = Force × Distance × cos

W=Force×Distance×cos(θ)

where:

Force is the force applied (300 N in this case),

Distance is the distance moved (30 m in this case),

θ is the angle between the force and the direction of motion. Since the force is applied horizontally and the mass is moved horizontally,

cos(θ) is 1.

So, in this case:

W = 300 N × 30 m × 1 = 9000 Joules

W=300N×30m×1=9000Joules

The work done by the force is 9000 Joules.

Now, power (P) is given by the formula:

P = W over t

where:

W is the work done (9000 J),

t is the time taken (3 seconds in this case).

P = 9000J over 3s = 3000 Watts

The power exerted is 3000 Watts.

So, the work done by the force is 9000 Joules, and the power is 3000 Watts.

I hope it helps...