Answer :
Final answer:
Using the concept of gravitational force and frictional force, the force required to maintain constant speed while a 112 kg firefighter slides down a pole is approximately 1100 N, which is not listed in any of the provided options.
Explanation:
This question pertains to the domain of physics, specifically involving concepts from classical mechanics like friction and gravitational force. The firefighter's motion down the pole is at a constant speed, implying that the downward gravitational force is equal to the upward frictional force, thereby maintaining equilibrium.
The gravitational force acting on the firefighter can be calculated by multiplying the firefighter's mass by gravity. Given the mass of the firefighter is 112 kg and the approximate gravity on Earth is 9.8 m/s², the gravitational force is 112 kg * 9.8 m/s² = 1097.6 N ≈ 1100 N.
Since the firefighter slides down the pole at a constant speed, the frictional force exerted by the pole to oppose this motion is equal to the gravitational force. Therefore, the frictional force is approximately 1100 N. However, this value is not listed in any of the options a, b, c, or d provided in the question, which could possibly due to an error in the question.
Learn more about Frictional Force here:
https://brainly.com/question/33562642
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