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------------------------------------------------ A feather is dropped on the moon from a height of 2 m. The acceleration of gravity on the moon is 1.69 m/s². Determine the time for the feather to fall to the surface of the moon.

By utilizing the distance formula for an object falling under constant acceleration (d = 1/2 * a * t²) and the given values, we find that it would take about 1.54 seconds for a feather to fall to the moon's surface from a height of 2 meters.

Explanation:

To calculate the time for the feather to fall to the surface of the moon, we can use the physics formula for distance traveled under constant acceleration, d = 1/2 * a * t² where d is the distance, a is acceleration and t is time.

Firstly, we rearrange the equation to solve for time, which gives us t = sqrt(2d/a). Using the given values d = 2 m (the height the feather is dropped from) and a = 1.69 m/s² (the acceleration due to gravity on the moon), substituting these into the formula gives us t = sqrt(2*2/1.69) = sqrt(2.37) = 1.54 s.

Therefore, it would take approximately 1.54 seconds for the feather to fall to the moon's surface from a height of 2 meters.

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