College

A farmer prepared 100 g of an aqueous solution of KNO3 in which the mole fraction of KNO3 was 0.1. Calculate the amount of KNO3 dissolved.

(Atomic masses are: K = 39.1 amu, N = 14 amu, and O = 16 amu.)

Answer :

The amount of [tex]KNO_3[/tex] dissolved would be 1011 grams.

Mole fraction

The mole fraction of a component of a substance is the ratio of the mole of the component relative to the mole of the whole substance.

Thus, for a mole fraction of KNO to be 0.1, it means 1 mole of KNO relative to 10 moles of KNO3.

In other words, the number of moles of [tex]KNO_3[/tex] dissolved is 10 moles.

Recall that: mole = mass/molar mass, and mass = mole x molar mass

Molar mass of [tex]KNO_3[/tex] = 39.1 + 14 + (16 x 3) = 101.1 g/mol

Mass of 10 moles of [tex]KNO_3[/tex] = 10 x 101.1

= 1011 grams

In other words, the amount of [tex]KNO_3[/tex] dissolved is 1011 grams.

More on mole fractions can be found here: https://brainly.com/question/29808190

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