High School

A driver in a car, originally moving at 12.2 m/s, applies the brakes until the car comes to a stop. The car moves a distance of 36.2 m while braking. How much time (in seconds) did it take for the car to stop? Assume constant acceleration during braking.

Answer :

The time taken for the car to stop, given that the car moves a distance of 36.2 m while the brakes were applied is 5.93 s

How to determine the time taken for the car to stop?

The following parameters where obtained from the given question:

  • Initial speed of car (u) = 12.2 m/s
  • Final speed of car (v) = 0 m/s
  • Distance traveled while the brakes where applied (s) = 36.2 m
  • Time taken (t) =?

[tex]s = \frac{(u + v)t}{2} \\\\36.2 = \frac{(12.2 + v)t}{2}\\\\36.2 = \frac{12.2t}{2}\\\\Cross \ multiply\\\\12.2t = 36.2 \times 2\\\\12.2t = 72.4\\\\Divide \ both \ sides \ by \ 12.2\\\\t = \frac{72.4}{12.2} \\\\t = 5.93 \ s\\\\[/tex]

Thus, the time taken is 5.93 s

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