High School

A dog pushes against the front door for 3 seconds with a force of 88 N. What impulse has the dog applied to the door?

A. 264 kg•m/s
B. 77.2 kg•m/s
C. 29.3 kg•m/s
D. 128 kg•m/s

Answer :

Final answer:

The impulse applied by the dog to the door is calculated by multiplying the force by the time. In this case, it's 88 N * 3 s, which equals 264 kg•m/s.

Explanation:

To solve this problem, we employ the concept of impulse in physics. Impulse is defined as the change in momentum of an object when a force acts upon it for an interval of time. It is calculated by taking the product of the force and the time over which it acts. In this case, the force is given as 88 N and the time is given as 3 seconds. So, we multiply the force (88 N) by the time (3 s) to get the impulse. Thus, the impulse applied by the dog to the door is 88 N * 3 s = 264 kg•m/s. Therefore, the correct answer is A. 264 kg•m/s.

Learn more about Impulse here:

https://brainly.com/question/34839253

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