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------------------------------------------------ A constant current of 913 mA flows through a light bulb. During a 45-minute period, the light bulb gives off 61 kJ of energy in the form of light and heat.

a) True
b) False

Voltage, current, and resistance are related to electric power in a light bulb. By calculating the power and energy output of the light bulb given the provided current and time period, we determine the given statement is false. the correct answer is B

Explanation:

Voltage, current, and resistance are related to electric power through the formula: Power (P) = Voltage (V) x Current (I). In this case, the light bulb has a constant current of 913 mA and gives off 61 kJ of energy during a 45-minute period. To determine whether this results in true or false, we can calculate the power using:
P = IV = 913 mA x 0.913 A = 0.913 W. Then, convert 45 minutes to hours (45/60 = 0.75 hours), and calculate the energy:
Energy = Power x Time = 0.913 W x 0.75 h = 0.68475 Wh = 0.68475 x 3600 J = 2464.1 J ≈ 2.46 kJ. Since the light bulb gives off 61 kJ of energy, the statement is false.