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------------------------------------------------ A car of mass 1.745 kg collides with a wall. The initial speed of the car is 18.9 m/s. After the collision, the car bounces in the opposite direction at a speed of 3.3 m/s. If the collision lasted for 163 ms, what was the average force in newtons exerted on the car by the wall? Express your answer to two decimal places with units of Newtons.

To find the average force exerted on the car by the wall, we can use the impulse-momentum principle. The average force exerted on the car by the wall is approximately -166.99 N.

Explanation:

To find the average force exerted on the car by the wall, we can use the impulse-momentum principle. The impulse is the change in momentum of the car, which can be calculated by subtracting the final momentum from the initial momentum. In this case, the initial momentum is the mass of the car multiplied by its initial speed, and the final momentum is the mass of the car multiplied by its final speed. The change in momentum is then divided by the duration of the collision to find the average force.

Firstly, calculate the initial momentum:

Initial momentum = mass x initial speed = 1.745 kg x 18.9 m/s = 32.9395 kg·m/s

Next, calculate the final momentum:

Final momentum = mass x final speed = 1.745 kg x 3.3 m/s = 5.7645 kg·m/s

Now, calculate the change in momentum:

Change in momentum = Final momentum - Initial momentum = 5.7645 kg·m/s - 32.9395 kg·m/s = -27.1750 kg·m/s

Lastly, divide the change in momentum by the duration of the collision in seconds to find the average force:

Average force = Change in momentum / Duration of collision = -27.1750 kg·m/s / 0.163 s = -166.9914 N

The average force exerted on the car by the wall is approximately -166.99 N.

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