Answer :
The ratio of the final to the initial energy stored in the capacitor is 9. Therefore the correct option is option E.
The capacitor's initial energy is determined by:
U_i equals frac12 CV_i2
where $V_i$ is the starting voltage and C is the capacitance.
The final amount of energy kept in the capacitor is determined by:
U_f is equal to frac (1/C(V_i + V_f)/2)
where the ultimate voltage, in this example 6 V, is denoted by the symbol $V_f$.
The final energy to starting energy ratio is:
= Fracture U_f = Fracture U_i
= Fracture Fracture 1 2 C (V_i + V_f) 2 Fracture 1 2 CV_i
= Fracture (V_i + V_f) 2 V_i
= Fracture (3+6) 2 3 2 = 9
As a result, the capacitor's end energy to starting energy storage ratio is 9. Response: E) 9.
For such more question on capacitor:
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