A brave but inadequate rugby player is being pushed backward by an opposing player who is exerting a force of 804 N on him. The mass of the losing player plus equipment is 83 kg, and he is accelerating at 1.17 m/s$^2$ backward.

What force in newtons (2 significant figures) does the winning player exert on the ground to move forward if his mass plus equipment is 118 kg?

To solve this problem, we can use Newton's second law of motion, which states that the force acting on an object is equal to the mass of the object multiplied by its acceleration.

Given:

Force exerted on the losing player (Flosing) = 804 N
Mass of the losing player (mlosing) = 83 kg
Acceleration of the losing player (alosing) = -1.17 m/s2
Mass of the winning player (mwinning) = 118 kg

Using Newton's second law of motion, we can calculate the force exerted by the winning player on the ground (Fwinning).

First, let's calculate the acceleration of the winning player using the given information:

awinning = Flosing / mlosing

awinning = 804 N / 83 kg

awinning ≈ 9.70 m/s2

Now, we can calculate the force exerted by the winning player on the ground:

Fwinning = mwinning * awinning

Fwinning = 118 kg * 9.70 m/s2

Fwinning ≈ 1142 N

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