High School

A box of mass 0.50 kg slides down a rough ramp with an initial speed of 2.0m/s. The ramp is inclined at an angle of 30° above the horizontal. The box slides a distance of 1.5m and comes to rest before reaching the bottom of the ramp. The energy dissipated as the box slides to a stop is most nearly

Answer :

Final answer:

The energy dissipated as the box slides to a stop is approximately 1 J.

Explanation:

When an object slides down a rough surface, some of its initial energy is lost due to friction. In this case, the box slides a distance of 1.5m and comes to rest before reaching the bottom of the ramp. This means that the box has lost some of its initial energy as it slid down the ramp.

The energy dissipated as the box slides to a stop can be calculated using the work-energy principle. The work done by the friction force is equal to the change in kinetic energy of the box. Since the box comes to rest, its final kinetic energy is zero. Therefore, the energy dissipated as the box slides to a stop is equal to its initial kinetic energy.

To calculate the initial kinetic energy, we can use the formula:

Kinetic Energy = 1/2 * mass * velocity^2

Plugging in the values, we have:

Kinetic Energy = 1/2 * 0.50 kg * (2.0 m/s)^2 = 1 J

Therefore, the energy dissipated as the box slides to a stop is approximately 1 J.