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------------------------------------------------ A battery of 6 V is connected to the terminals of a 3 m long wire of uniform thickness. What is the potential difference (in volts) between two points separated by 50 cm on the wire?

Answer :

Final answer:

The potential difference between two points separated by 50 cm on the wire connected to a battery of 6V will be 36V.

Explanation:

In this case, the potential difference between two points separated by 50 cm on the wire will be six times the potential difference of the battery. Since the battery has a potential difference of 6V, the potential difference between the two points on the wire will be 6 x 6V = 36V.

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