Answer :
Final answer:
To find the distance a car travels while slowing down at a constant rate, we can use the formula distance = initial velocity * time + 0.5 * acceleration * time^2. By rearranging the formula and plugging in the values, we can calculate the distance traveled.
Explanation:
To find the distance the car travels during the 5 seconds, we can use the formula:
distance = initial velocity * time + 0.5 * acceleration * time^2
Since the car is coming to a stop, its final velocity is 0 m/s. We can assume that the acceleration is constant, so we can rearrange the formula:
distance = initial velocity * time + 0.5 * acceleration * time^2 = (initial velocity * time) - 0.5 * acceleration * time^2
Plugging in the values, we have:
distance = (21.0 m/s * 5.00 s) - 0.5 * acceleration * (5.00 s)^2
Since we need to solve for distance, we can set up the equation:
distance = (21.0 m/s * 5.00 s) - 0.5 * distance = (105.0 m) - 0.5 * acceleration * 25.0 s^2
We don't know the value of acceleration, but we can solve for it by rearranging the equation:
0.5 * acceleration * 25.0 s^2 = 105.0 m - distance
acceleration = (105.0 m - distance) / (0.5 * 25.0 s^2)
Now we can substitute this value back into the distance equation:
distance = (21.0 m/s * 5.00 s) - 0.5 * ((105.0 m - distance) / (0.5 * 25.0 s^2)) * (5.00 s)^2
Solving this equation will give us the distance the car travels during the 5.00 seconds before coming to a stop.
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