Answer :
Final answer:
The resulting force of friction on a 94 kg motorcycle with a coefficient of kinetic friction of 0.700 is calculated to be 645 N when rounded to three significant digits.
Explanation:
The question asks for the resulting force of friction on a skidding motorcycle given the mass of the motorcycle and the coefficient of kinetic friction. To calculate the force of friction, which is the product of the coefficient of kinetic friction and the normal force (the weight of the motorcycle in this case), we use the equation
f_k = \\(mu k) * N.
The mass of the motorcycle (m) is 94 kg and the coefficient of kinetic friction (\\(mu k)) is 0.700. The normal force (N) is equal to the weight of the motorcycle, which is the product of the mass (m) and the acceleration due to gravity (g), approximately 9.81 m/s².
The calculation is as follows:
N = m * g
= 94 kg * 9.81 m/s²
= 922.14 N (rounded to five significant digits)
The resulting force of friction (f_k) is:
f_k = \\(mu k) * N
= 0.700 * 922.14 N
= 645.498 N
After rounding to three significant digits, the resulting force of friction is 645 N.
