A 93-kg astronaut is stranded away from his space shuttle. He throws a 2-kg hammer with a velocity of 15 m/s. How fast will he be propelled toward the shuttle, in m/s? (Round your answer to one decimal place if necessary.)

According to the conservation of momentum principle, if there is no external force acting on the colliding objects, the total momentum before and after the collision will be the same.

According to the idea of conservation of linear momentum, a body or system of bodies in motion preserves its total momentum, which is measured as the sum of its mass and vector velocity. Momentum is constantly maintained because an isolated system (like the universe) is devoid of external forces.

Given;

Mass of the astronaut, m₁ be 95 kg

Mass of the hammer thrown, m₂ be 2 kg

Velocity of the hammer, v₂ be 19 m/s

Let the recoil velocity of the shuttle be v₁

By using principle of conservation of linear momentum;

m₁v₁ = m₂v₂

simplifying the above equation, we get

v₁ = m₂v₂/m₁

substitute the values in the above equation,, we get

v₁ = (2 x 19) / 95

v₁ = 0.4 m/s

Therefore, at a speed of 0.4 m/s, the astronaut will be accelerated towards the direction of the shuttle.

To learn more about principle of conservation of linear momentum refer to;

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