Answer :
To determine the energy due to the bowling ball's position, we use the gravitational potential energy formula:
[tex]$$
E_{\text{pot}} = mgh,
$$[/tex]
where
[tex]\( m = 7.00 \, \text{kg} \)[/tex] is the mass of the ball,
[tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex] is the acceleration due to gravity, and
[tex]\( h = 2.00 \, \text{m} \)[/tex] is the height above the ground.
Substitute the given values into the formula:
[tex]$$
E_{\text{pot}} = 7.00 \times 9.80 \times 2.00.
$$[/tex]
Calculating the product:
[tex]$$
E_{\text{pot}} = 137.2 \, \text{J}.
$$[/tex]
Rounding this result to the nearest whole number gives:
[tex]$$
E_{\text{pot}} \approx 137 \, \text{J}.
$$[/tex]
Thus, the energy due to its position is [tex]\(\boxed{137 \, \text{J}}\)[/tex].
[tex]$$
E_{\text{pot}} = mgh,
$$[/tex]
where
[tex]\( m = 7.00 \, \text{kg} \)[/tex] is the mass of the ball,
[tex]\( g = 9.80 \, \text{m/s}^2 \)[/tex] is the acceleration due to gravity, and
[tex]\( h = 2.00 \, \text{m} \)[/tex] is the height above the ground.
Substitute the given values into the formula:
[tex]$$
E_{\text{pot}} = 7.00 \times 9.80 \times 2.00.
$$[/tex]
Calculating the product:
[tex]$$
E_{\text{pot}} = 137.2 \, \text{J}.
$$[/tex]
Rounding this result to the nearest whole number gives:
[tex]$$
E_{\text{pot}} \approx 137 \, \text{J}.
$$[/tex]
Thus, the energy due to its position is [tex]\(\boxed{137 \, \text{J}}\)[/tex].
