Answer :
Final answer:
The skier on the 23° hill is being pulled by a rope at a constant speed, implying zero net force. The pulling force from the engine-powered rope counteracts gravity acting on the skier along the inclined slope (equals to mg sin θ), ensuring a consistent speed up the hill. Friction and air resistance are not included in this case, assuming an ideal model of physics.
Explanation:
The physics in play with the skier on the incline comes down to understanding forces and acceleration. In this scenario where friction is ignored, the skier is being pulled uphill at a constant speed, indicating that net force on the skier is zero. This net force is comprised of the force of gravity on the skier opposing his journey uphill (W = mg sin θ where m = skier's mass, g = gravity, and θ = slope angle), and the force from the moving rope pulling the skier uphill.
The latter force equals the force of gravity on the skier ensuring constant velocity (F = ma where a = acceleration due to gravity). Therefore, the pulling force from the rope is equal to mg sin θ for the system to remain in equilibrium.
In terms of the physical scenario, the skier is being counteracted very specifically by the engine-powered rope, allowing him to travel at a stable speed along the inclined plane. Importantly, this representation negates air resistance and other forms of friction, suggesting a totally efficient system.
Learn more about Physics of inclined motion here:
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