Answer :
If the work done by friction is -10.0 kJ, the speed of the skier on reaching the bottom of the slope is 44.1 m/s.
The potential energy of the skier at the top of the slope is given by:
PE = mgh
where m is the mass of the skier, g is the acceleration due to gravity, and h is the height of the slope.
At the bottom of the slope, all of this potential energy will have been converted to kinetic energy, which is given by:
KE = (1/2)mv²
where v is the speed of the skier.
The work done by friction is given by:
W = -Fd
where F is the force of friction and d is the distance over which the force is applied.
Since the skier starts from rest, the initial kinetic energy is zero, so the total work done on the skier is equal to the work done by friction:
W = KE - PE = -10.0 kJ
(1/2)mv² - mgh = -10.0 kJ
v =√(2/m)(-10.0 kJ + mgh))
Substituting the given values, we get:
v = √((2/60 kg)(-10.0 kJ + (60 kg)(9.81 m/s²)(50 m)))
v ≈ 44.1 m/s
Therefore, the speed of the skier on reaching the bottom of the slope = 44.1 m/s.
Learn more about friction here:
https://brainly.com/question/30280752
#SPJ11
