Answer :
Final answer:
The magnitude of the normal force of the table on the 6.00 kg box is 58.8 N. This is calculated by determining the weight of the box (its mass times the acceleration due to gravity), which is equal to the normal force in this case.
Explanation:
The magnitude of the normal force exerted by the table on the box is equal to the weight of the box when there is no vertical acceleration. This is because the box is at rest and the net force in the vertical direction is zero. According to Newton's second law, net force equals mass times acceleration. Thus, with no acceleration, there are no net forces acting on the box. Therefore, the normal force equals the weight of the box.
To calculate the weight of the box, you multiply the mass of the box by the acceleration due to gravity. The mass is given as 6.00 kg and the acceleration due to gravity is typically 9.80 m/s² on Earth. Therefore, the weight of the box is (6.00 kg)(9.80 m/s²) = 58.8 N, which is also the magnitude of the normal force exerted by the table on the box.
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Answer:
to get it u have to multiple 6=00 time 89 to get the number 21 than plus it by 22 what is 31
