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------------------------------------------------ A 557−N force is applied to a 103−kg block, which is stationary before the force is applied. Determine the magnitude and direction of the friction force [tex]F[/tex] exerted by the horizontal surface on the block. The force is positive if to the right, negative if to the left.

A 557-N force is applied to a 103-kg block that is initially stationary. We need to determine the magnitude and direction of the friction force F exerted by the horizontal surface on the block.

To find this, we can use Newton's second law and consider the forces acting on the block. The magnitude of the friction force is found to be 557 N, and its direction is opposite to the applied force, which means the friction force is to the left (negative).

According to Newton's second law, the sum of the forces acting on an object is equal to its mass multiplied by its acceleration. In this case, the block is initially stationary, so its acceleration is zero. The forces acting on the block are the applied force (557 N) and the friction force (F). Since the block remains stationary, the net force acting on it must be zero.

Applying Newton's second law:

ΣF = m * a

Since a = 0, we have:

ΣF = 0

Considering the forces acting on the block, we have:

557 N - F = 0

Solving for F, we find:

F = 557 N

The magnitude of the friction force is determined to be 557 N. To determine its direction, we note that the applied force is positive (to the right). Since the block remains stationary, the friction force must oppose the applied force. Therefore, the direction of the friction force is to the left, which is negative.

To learn more about Newton's second law: -brainly.com/question/15280051

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