High School

A 500 kg vehicle is traveling down the street. At \( t = 0 \) seconds, its speed is 20 m/s. After 20 minutes, the vehicle generates 156 kJ of kinetic energy.

A) What is the kinetic energy of the vehicle at rest?

B) At time \( t = 20 \) minutes, what is the vehicle's speed?

C) Calculate the amount of work done between \( t = 0 \) and \( t = 20 \) minutes.

Answer :

a) The kinetic energy at rest is 0 J.

b) At t=20 minutes, the vehicle's speed remains 20 m/s, c) The amount of work completed between t=0 and t=20 minutes is 156 kJ.

a) The kinetic energy of an object is given by the formula KE = 1/2 * m * v^2, where m is the mass and v is the velocity. At rest, the velocity (v) is 0 m/s, so the kinetic energy is 0 J.

b) At t=20 minutes, the vehicle's speed remains constant at 20 m/s. The given information states that the vehicle generates 156 kJ of kinetic energy after 20 minutes, but it does not indicate a change in speed. Therefore, the speed remains 20 m/s.

c) The amount of work completed between t=0 and t=20 minutes can be calculated using the work-energy principle. The work done on an object is equal to the change in its kinetic energy. Since the kinetic energy increases by 156 kJ, the work done on the vehicle during this time interval is also 156 kJ.

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