High School

A 5.00-l tank contains helium gas at 1.50 atm. What is the pressure of the gas in kPa?

A. 5.00 kPa
B. 1140 kPa
C. 152 kPa
D. 0.0148 kPa
E. 760 kPa

Answer :

Final answer:

The pressure of helium gas at 1.50 atm is equivalent to 152 kPa when converted using the factor of 1 atm being approximately 101.325 kPa.

Explanation:

To convert the pressure of helium gas from atmospheres (atm) to kilopascals (kPa), you can use the conversion factor that 1 atm is approximately equal to 101.325 kPa. So, to find the pressure in kPa, you multiply the given pressure in atm by this conversion factor:

P (kPa) = P (atm) × 101.325 kPa/atm

For the given pressure of 1.50 atm:

P (kPa) = 1.50 atm × 101.325 kPa/atm = 152 kPa

Therefore, the pressure of the helium gas in kPa is 152 kPa, which corresponds to option (c).