Answer :
Final answer:
The pressure of helium gas at 1.50 atm is equivalent to 152 kPa when converted using the factor of 1 atm being approximately 101.325 kPa.
Explanation:
To convert the pressure of helium gas from atmospheres (atm) to kilopascals (kPa), you can use the conversion factor that 1 atm is approximately equal to 101.325 kPa. So, to find the pressure in kPa, you multiply the given pressure in atm by this conversion factor:
P (kPa) = P (atm) × 101.325 kPa/atm
For the given pressure of 1.50 atm:
P (kPa) = 1.50 atm × 101.325 kPa/atm = 152 kPa
Therefore, the pressure of the helium gas in kPa is 152 kPa, which corresponds to option (c).
