Answer :
The potential difference across a capacitor can be calculated by dividing the charge on the capacitor by its capacitance. In this case, with a charge of 37.9 μC and a capacitance of 56.9 pF, the potential difference is approximately 0.666 kV.
The capacitance C and the charge Q determine the potential difference V that exists across the capacitor. This is given by the equation V = Q/C. Thus, to determine the potential difference across the capacitor, we must determine the capacitance and charge first.
How to calculate the potential difference across the capacitor?
Capacitance is measured in farads (F), while charge is measured in coulombs (C). You can also calculate capacitance in picofarads (pF), and charge in microcoulombs (μC).
Let's first convert 56.9pF to farads:
F = pF/1,000,000 = 56.9 × 10⁻⁶ F
Now let's convert 37.9μC to coulombs:
C = μC/1,000,000 = 37.9 × 10⁻⁶ C
Now we can find the potential difference using the equation
V = Q/C.V = (37.9 × 10⁻⁶ C) / (56.9 × 10⁻⁶ F)
V = 0.666 kV
Thus, the potential difference across the capacitor is 0.666 kV.
To know more about potential difference, refer to the link below:
https://brainly.com/question/30544638#
#SPJ11
