Answer :
Final answer:
The problem requires finding the static friction force acting on a 3600 kg truck parked on a 14-degree slope, considering a coefficient of static friction of 0.90. The force is computed by combining the normal force derivative from the truck's weight with the given coefficient.
Explanation:
The question involves calculating the force of static friction acting on a parked truck on a slope, using the coefficient of static friction and the mass of the truck. First, we need to calculate the component of the truck's weight that acts parallel to the slope, which is equal to m imes g imes ext{sin}( heta), where m is the mass of the truck, g is the acceleration due to gravity, and heta is the angle of the slope. This force must be counteracted by static friction for the truck to remain parked without sliding down the slope.
The coefficient of static friction ( ext{ extmu}_s) between the truck tires and the road is given as 0.90. The normal force (N), which is the component of the truck's weight perpendicular to the slope, is equal to m imes g imes ext{cos}( heta). The maximum static friction force (f_{s_{max}}) can be found by multiplying the normal force by the coefficient of static friction:
f_{s_{max}} = ext{ extmu}_s imes N. For the 3600 kg truck on a 14-degree slope, the friction force can be calculated as follows:
f_{s_{max}} = 0.90 imes (3600 kg imes 9.81 m/s^2 imes ext{cos}(14^{ ext{o}}))
After calculating this expression, we will get the magnitude of the static friction force in newtons (N), rounded to two significant figures.
