High School

a) 340 ml + 18 cl + 9 l = ? cl

b) 899 l - 9000 ml - 830 dl = ? l

c) 980 cl - 8 l + 58 dl - 1200 ml = ? cl

Answer :

Let's break down the problem step-by-step for clarity. We'll approach each part separately.

Part (a):

Convert all the measurements to centiliters (cl) to add them up.

  1. 340 ml:

    • 1 milliliter (ml) = 0.1 centiliters (cl)
    • [tex]340 \text{ ml} \times 0.1 = 34 \text{ cl}[/tex]
  2. 18 cl:

    • Already in centiliters, no conversion needed.
  3. 9 l:

    • 1 liter (l) = 100 centiliters (cl)
    • [tex]9 \text{ l} \times 100 = 900 \text{ cl}[/tex]

Now, add them up:
(
34 \text{ cl} + 18 \text{ cl} + 900 \text{ cl} = 952 \text{ cl}
)

Part (b):

Convert all measurements to liters (l) to make calculation easier.

  1. 899 l:

    • Already in liters, no conversion needed.
  2. 9000 ml:

    • 1 milliliter (ml) = 0.001 liters (l)
    • [tex]9000 \text{ ml} \times 0.001 = 9 \text{ l}[/tex]
  3. 830 dl:

    • 1 deciliter (dl) = 0.1 liters (l)
    • [tex]830 \text{ dl} \times 0.1 = 83 \text{ l}[/tex]

Now, subtract the converted quantities from 899 l:
(
899 \text{ l} - 9 \text{ l} - 83 \text{ l} = 807 \text{ l}
)

Part (c):

Again, convert all to centiliters (cl).

  1. 980 cl:

    • Already in centiliters, no conversion needed.
  2. 8 l:

    • 1 liter (l) = 100 centiliters (cl)
    • [tex]8 \text{ l} \times 100 = 800 \text{ cl}[/tex]
  3. 58 dl:

    • 1 deciliter (dl) = 10 centiliters (cl)
    • [tex]58 \text{ dl} \times 10 = 580 \text{ cl}[/tex]
  4. 1200 ml:

    • 1 milliliter (ml) = 0.1 centiliters (cl)
    • [tex]1200 \text{ ml} \times 0.1 = 120 \text{ cl}[/tex]

Calculate:
(
980 \text{ cl} - 800 \text{ cl} + 580 \text{ cl} - 120 \text{ cl} = 640 \text{ cl}
)

Therefore, the final results are:

  • (a) 952 cl
  • (b) 807 l
  • (c) 640 cl