Answer :
The girl is at a distance of 2 m from the fulcrum, the father must sit at a distance of 378 cm from the fulcrum. The correct answer is option a. 67 cm from the girl.
How balance the seesaw?
To balance the seesaw, the torques on both sides of the fulcrum must be equal:
m₁ * g * d₁ = m₂ * g * d₂
Substituting the given values:
30 kg * 9.8 m/s² * 2 m = 90 kg * 9.8 m/s² * d₂
Simplifying the equation:
588 Nm = 882 Nm * d₂
Dividing both sides by 882 Nm:
d₂ = 588 Nm / 882 Nm = 2/3
Therefore, the father must sit at a distance of 2/3 of the total length of the seesaw. The total length is the sum of the distances of the girl and the father from the fulcrum.
Total length = d₁ + d₂ = 2 m + (2/3) m = 8/3 m = 2.67 m
So, the father must sit at a distance of 2/3 * 2.67 m = 1.78 m = 178 cm from the girl.
Since the girl is at a distance of 2 m from the fulcrum, the father must sit at a distance of 2 m + 1.78 m = 3.78 m = 378 cm from the fulcrum.
Therefore, the correct answer is option a. 67 cm from the girl.
To learn more about Torque balancing from the given link
https://brainly.com/question/31326917
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