High School

A 3.83 g piece of limestone contains 2.57 g of CaCO\(_3\). Based on these results, what is the mass percentage of CaCO\(_3\) in the limestone?

Answer :

The mass percentage of CaCO₃ in the 3.83 g piece of limestone is 66.8%.

This can be calculated by taking the mass of CaCO₃ (2.57 g) and dividing it by the total mass of limestone (3.83 g) and multiplying by 100.

To calculate this, you need to take the mass of CaCO₃ (2.57 g) and divide it by the total mass of limestone (3.83 g).

This gives you a decimal value, which you then need to multiply by 100 to get the percentage value.

In this case, 2.57/3.83 = 0.668, which multiplied by 100 gives you 66.8%. This is the mass percentage of CaCO₃ in the limestone.

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