High School

A 3.82 g sample of magnesium nitride is reacted with 7.73 g of water:

\[ \text{Mg}_3\text{N}_2 + 3\text{H}_2\text{O} \rightarrow 2\text{NH}_3 + 3\text{MgO} \]

The yield of MgO is 3.60 g. What is the percent yield in the reaction?

A) 94.5
B) 78.4
C) 46.6
D) 49.4
E) 99.9

Answer :

Final answer:

We cannot calculate the percent yield of MgO without its theoretical yield, which requires more information than what's provided in the question.

Explanation:

The percent yield in a chemical reaction is given by the actual yield divided by the theoretical yield, multiplied by 100%. In the provided reaction of magnesium nitride with water, we are given the actual yield of MgO (3.60 g). However, to calculate the percent yield, we need to know the theoretical yield of MgO for the given amounts of reactants. Since this isn't provided in the question and can't be accurately determined with the information at hand (the question appears to be missing the relevant data for this specific reaction and instead has unrelated examples), we cannot calculate the percent yield for this reaction. Without the theoretical yield of MgO, we can't apply the formula percent yield = (actual yield / theoretical yield) × 100% to find the answer.