Answer :
The increase in length of the loaded wire is[tex]1.00 x 10^-8 m.[/tex]
To find the increase in length, we can use Hooke's Law, which states that the extension of a spring (or wire in this case) is directly proportional to the applied force. The formula for linear elastic deformation is ΔL = (F * L) / (A * E), where ΔL is the increase in length, F is the force applied, L is the original length, A is the cross-sectional area, and E is the Young's modulus. Plugging in the given values, we get:
ΔL = (F * L) / (A * E)ΔL = (200 * 4.00) / (0.2 * 8.00 x 1010)ΔL = 1.00 x 10-8 m
Therefore, the increase in length is 1.00 x 10-8 m.
To know more about Hooke's Law visit:
https://brainly.com/question/29126957
#SPJ11
