Answer :
Final answer:
The bike with an initial speed of 28.3 m/s and a mass of 147 kg slides about 153 meters before coming to a halt on a slippery road with a coefficient of kinetic friction of 0.27.
Explanation:
This problem involves kinetic friction and energy. Here we will use physics formulas about kinetic energy and work to solve this problem. The motorbike has an initial kinetic energy due to its movement, which is given by the formula:
Kinetic energy = 0.5 * mass * (speed)2
This energy is dissipated through the work done by kinetic friction as the bike slides to a halt. It's given by the formula:
Frictional work = Frictional force * distance
And the frictional force is equal to the normal force (equal to the weight of the motorbike in this case) times by the coefficient of kinetic friction.
µk * m * g * d = 0.5 * m * v2
Solve for d (distance), we get d = v2 / (2 * µk * g).
Plugging the given values and using 9.8 m/s2 as the gravitational acceleration, we get d = (28.3)2 / (2 * 0.27 * 9.8) ≈ 153 meters. So, the bike slides about 153 meters before it comes to the halt.
Learn more about Kinetic Friction here:
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