High School

A 143-lb woman regularly exercises on a treadmill at a speed of 5.5 mph and a 2% elevation. What is her caloric expenditure?

Answer :

The 143-lb woman burns approximately 312 calories during her 30-minute treadmill workout at a speed of 5.5 mph and a 2% elevation.

The caloric expenditure of the 143-lb woman can be estimated using the following formula:

Calories Burned = (METs x weight in kg x time in hours)
where METs (metabolic equivalent) is a measure of energy expenditure during physical activity.

For walking or running on a treadmill, the MET value depends on the speed and elevation. At 5.5 mph and 2% elevation, the MET value is about 9.5.

Converting the weight of the woman to kilograms, we get:

Weight = 143 lbs / 2.205 lbs/kg = 64.9 kg

Assuming that she exercises for 30 minutes, we can convert the time to hours:

Time = 30 minutes / 60 minutes/hour = 0.5 hours

Using the formula, we can calculate her caloric expenditure:

Calories Burned = (9.5 x 64.9 x 0.5) = 312 calories

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