Answer :
In this case, the period of oscillation for the system with the 13.6 kg mass attached to the spring with a spring constant of 116 N/m, and stretched 17 m away from the equilibrium position, is approximately 2.15 seconds.
1. Given data:
- Mass (m) = 13.6 kg
- Spring constant (k) = 116 N/m
- Displacement from equilibrium position (x) = 17 m
2. The period of oscillation (T) for a mass-spring system can be calculated using the formula:
T = 2π * √(m / k)
3. Substitute the given values into the formula:
T = 2π * √(13.6 / 116)
4. Calculate the period of oscillation:
T = 2π * √(0.1172)
T = 2π * 0.3424
T ≈ 2.15 seconds
Therefore, the period of oscillation for the system with the 13.6 kg mass attached to the spring with a spring constant of 116 N/m, and stretched 17 m away from the equilibrium position, is approximately 2.15 seconds.
