A 1200kg car initially moving at 20metre per second strikes a tree and comes to rest in a distance of 1.5m find the average stopping force the tree exerts on the car.

Question

High School

Answer :

dugarniharika9045 dugarniharika9045 · Answer 1 · 2024-12-15T09:18:01-05:00

The average stopping force exerted by the tree on the car is approximately -160,000 N.

To find the average stopping force exerted by the tree on the car, we can use the equation:

Force = mass × acceleration

First, let's find the acceleration of the car using the equation:

Final velocity² = Initial velocity² + 2 × acceleration × distance

Given: Initial velocity (u) = 20 m/s, Final velocity (v) = 0 m/s, and Distance (s) = 1.5 m

Substituting the values into the equation, we have:

0² = 20² + 2 × acceleration × 1.5

Acceleration = (0 - 400) / (2 × 1.5)

Acceleration = -400 / 3

Now, substituting the mass of the car (m = 1200 kg) and the calculated acceleration (a = -400/3 m/s²) into the force equation, we get:

Force = 1200 kg × (-400/3 m/s²)

Calculating the force, we find:

Force ≈ -160,000 N

The average stopping force exerted by the tree on the car is approximately -160,000 N.

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