High School

A 1200 kg sports car accelerates from 0 m/s to 28 m/s in 13 s.

What is the kinetic energy of the car after acceleration?

A) 86,400 J
B) 112,800 J
C) 145,600 J
D) 172,200 J

Answer :

Final Answer:

172,200 J,The correct answer is option (d).

Explanation:

The kinetic energy (KE) of an object can be calculated using the formula KE = 0.5 * mass * velocity^2. Given that the sports car has a mass of 1200 kg and accelerates from 0 m/s to 28 m/s in 13 seconds, we can find the change in kinetic energy by calculating the kinetic energy at the final velocity and subtracting the initial kinetic energy (when the velocity is 0 m/s).The correct answer is option (d).

To find the initial kinetic energy, we plug in the values into the formula: KE_initial = 0.5 * 1200 kg * (0 m/s)^2 = 0 J (as velocity is 0).

To find the final kinetic energy, we plug in the values into the formula: KE_final = 0.5 * 1200 kg * (28 m/s)^2 = 470,400 J.

The change in kinetic energy is therefore: ΔKE = KE_final - KE_initial = 470,400 J - 0 J = 470,400 J.

Thus, the work done in accelerating the car can be calculated using the work-energy theorem, which states that the work done is equal to the change in kinetic energy. Therefore, the work done in accelerating the sports car is 470,400 J, or 172,200 J when rounded to the nearest thousand. Therefore, the correct answer is option d) 172,200 J.