A 12,500 kg jet airplane starts its takeoff from rest on a runway. Its engines generate 29,193 N of thrust during the first 80 meters of the plane's motion. How much work was done by the engines?

In the given situation, the work done by the jet engines on the airplane equals the force generated by the engines multiplied by the distance covered. This is calculated as (29,193 N) * (80 m) = 2,335,440 Joules.

Explanation:

In physics, the work done by a force on an object is calculated as the force multiplied by the distance over which the force is applied and the cosine of the angle between them. In this situation, the force of the jet engines is given as 29,193 Newtons and the distance over which this force has been applied is 80 meters. As the thrust is along the direction of motion (angle = 0 degrees), the work done by the jet engines = (29,193 N) * (80 m) * cos (0°) = 2,335,440 Joules.

To elaborate, this calculation is based on the concept of work and energy in physics. Work done on an object is essentially the energy transferred to that object by a force. In this case, the jet engines are doing work on the airplane by applying a thrust force over a certain distance, thereby giving the airplane kinetic energy to take off.

It's important to note that the mass of the airplane and its initial rest state are not needed to solve this problem. It would come into play if we were to calculate the final speed of the airplane or the time it took to reach a certain speed, but for work done, we only need the force and the distance.

Learn more about Work and Energy here:

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