Answer :
Rocket comes to a momentary stop, accelerates to a speed of 382 m/s, and then reverses course. The change in kinetic energy during this operation is equal to 279.390J
The settings provided;
Time of motion of the rocket, t = 139 s, rocket velocity, v = 382 m/s, rocket acceleration, a = 1066kg.
The second kinematic equation, as shown below, is used to compute the rocket's distance travelled after the specified time;
s = ut + ¹/₂at²
s = (139 x 12) + (0.5 x 382 x 1066²)
s = 420 + 3600
s = 4020m
The energy that a body has because it is in motion is known as kinetic energy. Particles in solids are packed very firmly and closely together. Inside the solid, they are not at liberty to move. Only when energy is given to them, such as when the solid is heated, can they oscillate around their mean position. Particles' kinetic energy is caused by their velocity. Even if the particles move, their velocity will be very, very modest if they don't move at all. Hence, there will be very little kinetic energy.
E[K] = 1/2 mv²
E[K]=0.5×4020×139
=279.390J
As a result, m is the distance covered by the rocket after the specified amount of time.
Learn more about kinetic energy here
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The Complete Question is
a 1066 kg rocket travels through empty space with velocity 139 m/s . in order to turn around, the astronaut fires reverse thrusters which, over time, brings the rocket briefly to rest, and then to velocity 382 m/s with the rocket now traveling in the opposite direction. during this process, the change in kinetic energy is equal to alterations in energy that are occurring in the Rocket?
