High School

A 1000-kg automobile is raised by a hydraulic lift with a 196-N force applied to the input piston. What input force is needed to lift a 1500-kg truck?

Answer :

In this scenario, the hydraulic lift is used to lift an automobile weighing 1000 kg. The force required to lift the car is 196 N. To determine the area of the input piston, we can use the equation A = F/P, where A is the area, F is the force, and P is the pressure.

Given:

Weight of the car = 1000 kg

Force required to lift the car = 196 N

We can calculate the pressure P using the weight of the car:

P = Weight of the car / Area

P = 196 N / Area

To find the area of the input piston, rearrange the equation:

Area = 196 N / P

Now we need to calculate the input force required to lift the heavier truck. Let's assume the input and output pistons have the same diameter, so the area of the output piston is equal to the area of the input piston.

Given:

Weight of the truck = 1500 kg

Area of the output piston = Area of the input piston

To find the input force needed to lift the truck, we can use the equation F = P × A:

Input force = P × Area of the input piston

Substituting the values:

Input force = P × Area = (196 N / Area) × Area = 196 N

Therefore, an input force of 294 N is needed to lift the heavier truck.

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